Integrand size = 13, antiderivative size = 19 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {a}{2 x^2}-\frac {2 b}{3 x^{3/2}} \]
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Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {14} \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {a}{2 x^2}-\frac {2 b}{3 x^{3/2}} \]
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Rule 14
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a}{x^3}+\frac {b}{x^{5/2}}\right ) \, dx \\ & = -\frac {a}{2 x^2}-\frac {2 b}{3 x^{3/2}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=\frac {-3 a-4 b \sqrt {x}}{6 x^2} \]
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Time = 0.02 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.74
method | result | size |
derivativedivides | \(-\frac {a}{2 x^{2}}-\frac {2 b}{3 x^{\frac {3}{2}}}\) | \(14\) |
default | \(-\frac {a}{2 x^{2}}-\frac {2 b}{3 x^{\frac {3}{2}}}\) | \(14\) |
trager | \(\frac {\left (-1+x \right ) a \left (1+x \right )}{2 x^{2}}-\frac {2 b}{3 x^{\frac {3}{2}}}\) | \(20\) |
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none
Time = 0.25 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.79 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {4 \, b \sqrt {x} + 3 \, a}{6 \, x^{2}} \]
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Time = 0.20 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=- \frac {a}{2 x^{2}} - \frac {2 b}{3 x^{\frac {3}{2}}} \]
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none
Time = 0.20 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.79 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {4 \, b \sqrt {x} + 3 \, a}{6 \, x^{2}} \]
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none
Time = 0.27 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.79 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {4 \, b \sqrt {x} + 3 \, a}{6 \, x^{2}} \]
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Time = 0.03 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.68 \[ \int \frac {a+b \sqrt {x}}{x^3} \, dx=-\frac {a}{2\,x^2}-\frac {2\,b}{3\,x^{3/2}} \]
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